Отправлено: 14.10.12 14:16. Заголовок: Binary and random access file

The program should store the employee’s records in a random access file and supports a variety of operations  
 such as add a new employee record, modify an employee record, search and display employee records, etc. 
 & 
 You are to use a binary file to keep the records of all employees.  Identify and define a suitable structure to keep your employee record. 

as this mean isnt

const int RecordSize = ... 
  
 void readRecord(Employee *theEmployee , int index){ // Note that you have an index instead of size 
  
 	ifstream inFile; 
 	 
 	inFile.open( "employee.txt" ); 
  
 	if( inFile.is_open() ){ 
 			if(inFile.seekg(index * RecordSize)){ // index * RecordSize is the offset of your record 
 					getline( inFile , theEmployee->EmployeeID ); // Note that you do not have an array anymore 
 					getline( inFile , theEmployee->EmployeeName ); 
 					getline( inFile , theEmployee->EmployeeDepartment ); 
 					getline( inFile , theEmployee->EmployeeDOB ); 
 					getline( inFile , theEmployee->EmployeeAddress ); 
 					inFile >> theEmployee->EmployeeWorkHours; 
 					inFile >> theEmployee->PayRate; 
 					inFile >> theEmployee->totalSalary; 
 			} 
 			inFile.close(); 
 		} 
 	} 
 }

isnt the coding correct ? as we use the binary file to keep the record

isnt mean when ofstream . using

ios :: binary

thats all?

 Отправлено: 14.10.12 17:27. Заголовок: You should correctly..

You should correctly set the file open mode specifying that it is a binary file and is opened for read/write (I/O) operations.

 Отправлено: 15.10.12 06:28. Заголовок: mean infile.open (&#..

mean infile.open ("employee.txt" , ios:: binary )?

i get an fatal error that stated 1 unresolve external

 Отправлено: 15.10.12 13:55. Заголовок: It means that you ar..

It means that you are using a name that is undefined. Usually such error message conttains a reference to a name that is undefined.

 Отправлено: 15.10.12 14:21. Заголовок: i solved it . but as..

i solved it .
but as coder777 said in forum.

i cant read any data in case i use random access file.

void readRecord(Employee *theEmployee , int &index){ // Note that you have an index instead of size 
  
 	ifstream inFile; 
 	string filename; 
  
 	cout << "Enter filename to be read : "; 
 	getline( cin, filename ); 
 	inFile.open( filename.c_str() , ios :: binary ); 
  
 	if( inFile.is_open() ){ 
 			if(inFile.seekg(index * RecordSize)){ // index * RecordSize is the offset of your record 
 					getline( inFile , theEmployee->EmployeeID ); // Note that you do not have an array anymore 
 					getline( inFile , theEmployee->EmployeeFirstName ); 
 					getline( inFile , theEmployee->EmployeeLastName ); 
 					getline( inFile , theEmployee->EmployeeDepartment ); 
 					getline( inFile , theEmployee->EmployeePosition ); 
 					inFile >> theEmployee->EmployeeWorkHours; 
 					inFile >> theEmployee->PayRate; 
 					inFile >> theEmployee->totalSalary; 
 			} 
 			inFile.close(); 
 	} 
 }

erm , now what my problem ? i cannot display the data inside my file .

 Отправлено: 15.10.12 16:45. Заголовок: I already showed you..

I already showed you what functions you should use with a file opened in the binary mode. So I do not understand what you are doing.
There is such book by Herb Schildt "Herb Shildt's C++ Programming Cookbook". I think it will be useful if you will read this book.