Отправлено: 08.11.14 07:03. Заголовок: combinations find in 1d array

how can i display only same value starting and ending groups in a 1d array

this is the example array

int a[12]={2,1,1,2,2,4,5,4,5,4,5,4};

i need to find all combination in this array
output .........

2,1,1,2
4,5,4
5,4,5
4,5,4
5,4,5
4,5,4

 Отправлено: 08.11.14 07:26. Заголовок: Why are there absent..

Why are there absent combinations 1 1 and 2 2?

 Отправлено: 09.11.14 08:20. Заголовок: for example this is ..

for example this is a combination 4 5 4

a combination need its first value and last value matching and also minimum three value
below combinations i don't want to pick

1 1 1
1 2 5 1
1 1

 Отправлено: 09.11.14 08:30. Заголовок: I have not understoo..

I have not understood why this combination

1 2 5 1

does not satisfy the condition? Is it because 2 and 5 are unequal each other?

 Отправлено: 09.11.14 11:24. Заголовок: If I have understood..

If I have understood correctly what you need is the following

 
 #include <iostream> 
 #include <algorithm> 
 #include <iterator> 
 #include <functional> 
  
 template <typename ForwardIterator> 
  
 void display_ranges( ForwardIterator first,  
                      ForwardIterator last, 
                      std::ostream &os = std::cout ) 
 { 
 	typedef typename std::iterator_traits<ForwardIterator>::value_type value_type; 
 	 
 	ForwardIterator next; 
  
 	first = std::adjacent_find( first,  
 	                            last,  
 	                            std::not_equal_to<value_type>() );  
  
 	if ( first != last )		        
 	{	         
 	while ( ( next = std::adjacent_find( std::next( first ),  
 	                                     last, std::not_equal_to<value_type>() ) ) 
 	        != last ) 
 	{ 
 		if ( *first == *std::next( next ) ) 
 		{ 
 			std::copy( first, std::next( next, 2 ), 
 			           std::ostream_iterator<value_type>( os, " " ) ); 
 			os << std::endl; 
 		} 
 		 
 		first = next; 
 	} 
 	} 
 } 
  
 int main()  
 { 
 	int a[] = { 2, 1, 1, 2, 2, 4, 5, 4, 5, 4, 5, 4 }; 
 	 
 	display_ranges( std::begin( a ), std::end( a ) ); 
 	 
 	return 0; 
 } 
 

The output will be

 
 2 1 1 2  
 4 5 4  
 5 4 5  
 4 5 4  
 5 4 5  
 4 5 4  
 

 Отправлено: 09.11.14 17:21. Заголовок: yes exactly what i n..

yes exactly what i needed thank's